Serial.println printing just after the previous string in same line

Question

I wrote serial.println in my code but the string was printed in same line on serial moniter.

#include <WiFi.h>//for connecting esp32 to a wifi

#include <TinyGPS++.h>//to obtain gps data from neo-6m gps module 

#define WIFI_SSID "Airtel_pawa_4182"//wifi name in simple words
#define WIFI_PWD "Ahuja6230"//wifi password

TinyGPSPlus GPS;//creating a gps object from tinygps++ library

void setup() {
 Serial.begin(9600);
  //wifi setup{
  WiFi.begin(WIFI_SSID, WIFI_PWD);
  Serial.println("connecting to wifi");
  while(WiFi.status() != WL_CONNECTED){
   Serial.println(".");
   delay(1000);    
  }
  Serial.println("Successfully connected to ");
  Serial.print(WIFI_SSID);
  //}

  //gps setup{
  Serial2.begin(9600);
  delay(1000);
  Serial.println("ESP32-GPS Tracker");
  Serial.println("Initializing...");
  //}
}

void loop() {
}

In this code the string "esp32-gps tracker" is printing just after the previous string in same line on serial moniter.

I tried running code again and again but it didn't work...

I am using esp32 board(just a detail)

What do i do?

Answer 1

The previous print statements are these:

  Serial.println("Successfully connected to ");
  Serial.print(WIFI_SSID);

The SSID won't be terminated by a newline. Perhaps you meant:

  Serial.print("Successfully connected to ");
  Serial.println(WIFI_SSID);

?

Answer 2

To follow on from previous answer, your solution is to either:

• change the previous Serial.print() to a Serial.println() so that that text is followed by a line end, or
• add a \n to the front of the line you are having the problem with, so it starts with a new line, to make up for the "missing" new line in the previous Serial.print().

Answer 3

When sending text through a serial line, it is customary to terminate each line with some sort of end-of-line marker: you print some text, and immediately after it the EOL to signify that “this is now a complete line”. Accordingly, the Serial.println() method prints the requested text, immediately followed by the EOL marker (in this case, CR+LF).

From your question, you seem to be thinking that the EOL immediately precedes the text. This is not the case.

See JRobert's answer for the correct way to build a line from multiple print statements: println() should be use on the last piece, not on the first one.