dot matrix arduino turn off the intermittent led

Question

I made a dot matrix that contain 10 row and 12 column , total 120 led.

I want to turn on the leds like this picture but when I open ground 1 , 2 and pin 0 , 1 , 2

6 leds light together.what kind of structure should I build?

Sheme :

I tried row by row like this:

 clear_cube();
 regWrite(cube[0][0], HIGH);
 set_array(4);
 //delay(10);

clear_cube();
regWrite(cube[1][0], HIGH);
set_array(3);
//delay(10);

clear_cube();
regWrite(cube[0][0], HIGH);
set_array(2);
//delay(10);                                                                                                                                 When I decrease the delay 5 leds blinking.

100 50 10 0 delay Youtube

Answer 1

You can't just turn them on like that.

Instead you have to turn one row on. Then the next row. Then the next. Very fast.

So you first display:

O@OO
OOOO
OOOO

Then you display

OOOO
OO@O
OOOO

Then you display

OOOO
OOOO
O@OO

And you cycle through that very fast. Usually using a timer to run it all. The fact that you're using '595s will slow you down and make it harder to update fast enough to look non-flickery.

Answer 2

You want to multiplex them by rows or columns. If you do it by columns, then do the following: Set all columns to open circuit. (everything off.)

Set the row value pins for the first column, then activate the column pin for the first column. The LEDs for the first column light up.

Now delay for a brief period (say 20 ms) and go on to the next column. (Obviously you'd use a loop for this.) Repeat.

You should write your code as a state machine using millis() rather than using delay, or you will paint yourself into a corner and you'll write code that totally blocks the machine just to display the LED grid. If you use millis() and a sate machine you'll be able to do other things at the same time you loop through the LEDs