I happened to be looking through the HardwareSerial.cpp file that contains the functions used for Serial communication for Arduino. While looking through the HardwareSerial::begin(baud, config) function, I noticed that the ucsra register has its U2X0 bit set. When I looked through the datasheet, it says that the U2X0 bit is set to start Double Speed Operation. From what I'm reading, this means that the baud rate is doubled.
I've been using this Arduino on this computer for a while now with no complaints for the baud rate being at an incorrect speed. What is Double Speed Operation? Why does it seem to be set in the code by default? I attached the code and section in the manual below.
void HardwareSerial::begin(unsigned long baud, byte config)
{
// Try u2x mode first
uint16_t baud_setting = (F_CPU / 4 / baud - 1) / 2;
*_ucsra = 1 << U2X0;
// hardcoded exception for 57600 for compatibility with the bootloader
// shipped with the Duemilanove and previous boards and the firmware
// on the 8U2 on the Uno and Mega 2560. Also, The baud_setting cannot
// be > 4095, so switch back to non-u2x mode if the baud rate is too
// low.
if (((F_CPU == 16000000UL) && (baud == 57600)) || (baud_setting >4095))
{
*_ucsra = 0;
baud_setting = (F_CPU / 8 / baud - 1) / 2;
}
// assign the baud_setting, a.k.a. ubrr (USART Baud Rate Register)
*_ubrrh = baud_setting >> 8;
*_ubrrl = baud_setting;
_written = false;
//set the data bits, parity, and stop bits
#if defined(__AVR_ATmega8__)
config |= 0x80; // select UCSRC register (shared with UBRRH)
#endif
*_ucsrc = config;
sbi(*_ucsrb, RXEN0);
sbi(*_ucsrb, TXEN0);
sbi(*_ucsrb, RXCIE0);
cbi(*_ucsrb, UDRIE0);
}