1

Looking to merge two different 2D arrays of different row sizes into one long array:

 int 2dArray1[][] = {
   {1, 2, 3},
   {4, 5, 6}};
 int 2dArray2[][] = {
   {10, 20},
   {30, 40}};
 int 1dLongArray[10];

This is where I need help in order to have the values of 1dLongarray be arranged as follows:

1, 2, 3, 10, 20, 4, 5, 6, 30, 40

How would I achieve this? Thanks in advance.

3
  • step by step, how did you do it on paper? ... the program would do it the same way
    – jsotola
    Nov 29 '20 at 23:37
  • The only way that I could think to make it work on paper would be to use memcpy for a one dimensional arrays and then create a two dimensional array out of it somehow. I'm not really sure how to do that, and I'm fairly new to coding and don't have a tutor or instructor to help me. I always try to do my best to find an answer myself before asking online but this one had me stumped.
    – Hitachii
    Nov 30 '20 at 1:47
  • when i say on paper, i mean, how would you do it if you knew nothing about programming ... what sequence of steps would you follow? ... i also do not mean write down first three numbers ... i mean baby steps, like look at array1, row1, position1. copy content to first empty position at destination
    – jsotola
    Nov 30 '20 at 1:56
0

Consider using loops of length specific to the desired number of transactions. For example, using this pseudo code create a sketch which follows this pattern:

initialize i to zero
loop 2 times for each row using the variable x
  loop 3 times for each element in first array using the variable y
    long array [i] = first array[x][y] 
    increment i
  loop 2 times for each element in a second array using the variable z
    long array [i] = second array[x][z]
    increment i
5
  • Being a brand new account I can't upvote your comment yet, so I'm leaving this comment to thank you!
    – Hitachii
    Nov 30 '20 at 1:42
  • If you can derive a working solution from this answer, you should be able to accept this answer as a solution to your question.
    – st2000
    Nov 30 '20 at 1:49
  • Thanks @Hitachii for making the answer as correct. If the answer works great! If not, please leave a comment and I'll edit the answer to improve it.
    – st2000
    Nov 30 '20 at 14:54
  • Sure. If someone were to plug the guideline for the formula that you posted, into the problem that I posted, for "long array [i] = first array [y] [x]" and "long array [i] = second array [z][x], they would have to switch the placement of x and z/y in their respective line to look like "long array [i] = first array [x][y]" to follow the original sequence of the array. Do I post my working code? This shows how green I am to this platform.
    – Hitachii
    Nov 30 '20 at 21:10
  • You are correct. The 1st argument is the row and the second is the column. I'll change my answer.
    – st2000
    Dec 1 '20 at 5:37

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