1

I am trying to control a servo using keyboard.

void loop() {
if (Serial.available() > 0) {
  x = Serial.parseInt();
  while(pos < 180){
  pos = x + pos;
  Serial.println(pos);
  myservo.write(pos);
  delay(100);
 }
  }
else if(Serial.available() > 0){
if(pos>=180){
  pos = 0;
  delay(500);
  myservo.write(0);

  }
  }
 }

Right now the servo takes the input correctly. The only thing is that it wont change positions immediately. It will wait until it hits 180 resets to 0 and then use the input I put in. This isnt the behaviour I want. I want it to change immediately. How Do I set this up?

1 Answer 1

1

I don't understand why you use 2 Serial.available condition.
I try to rewrote your program based on my imagination, so do not hate me if its wrong.
Why don't you try this and tell the results:

int pos = 0,x=0;
void loop() 
{
  while (Serial.available() > 0) x = Serial.parseInt();

  pos+=x;
  if (pos>180) pos = 0;
  myservo.write(pos);
  Serial.println (pos);
  delay(100);
}
5
  • I should've been more clear. I want to rotate the servo from 0-180, and once the servo goes past 180 I want to reset it back to 0
    – Elchapo
    Commented Nov 11, 2016 at 7:20
  • Can you explain what is the serial input used for?
    – duck
    Commented Nov 11, 2016 at 7:22
  • Getting input from the keyboard. I put in a value between 1-90 and It should rotate the servo that much. Once the servo rotates more than 180 degrees then it should reset to 0; I want to set it up so that immediately upon receiving input it rotates that much. Right now it waits until it resets to adjust the amount I rotate the servo
    – Elchapo
    Commented Nov 11, 2016 at 7:26
  • I think I got your objective. Answer updated
    – duck
    Commented Nov 11, 2016 at 7:28
  • Thank you. I was complicating it with all the if statements and conditions. Your answer makes much more sense Thank
    – Elchapo
    Commented Nov 11, 2016 at 7:31

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