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Aug 22, 2021 at 19:39 comment added Juraj @mehmet, it is common C++ object member access you asked about
Aug 22, 2021 at 19:32 comment added Michel Keijzers @Juraj Thanks for that addition (I was not sure, so I removed the comment about not being sure and the statement in my answer).
Aug 22, 2021 at 19:32 history edited Michel Keijzers CC BY-SA 4.0
deleted 57 characters in body
Aug 22, 2021 at 13:16 comment added JRobert If you have access to the object itself, e.g., Serial, you can say Serial.println(). If your library only has a pointer to the object, you have use ->, the dereference operator: serialPtr->println(). The result is the same: calling the object's 'println()' member. The difference is in how the compiled code gets you to that member.
Aug 22, 2021 at 12:32 comment added mehmet Can i ask a last question, why second method uses "->" and Why not "." Such us _serial.begin(baud). Is this totally same
Aug 22, 2021 at 11:21 comment added Juraj there is no Serial base class
Aug 22, 2021 at 11:00 history answered Michel Keijzers CC BY-SA 4.0