A relay, as pictured, is a good choice. It provides complete galvanic isolation and switches the power properly.
Another option is to use a MOSFET that can handle enough current (an N-channel switching the ground as a low side switch, or a P-channel switching the power which is itself switched by an N-channel, as a high side switch).
The simplest fix to your problem is to change the map() call to
byte alrmSet = map(alrmSwState, 0, 1024, 0, 3);
In the call above, the mapped intervals are of the semi-open type, e.g.
[a, b), where the start values (namely 0) are understood as being
inclusive and the end values (1024 and 3) are exclusive.
Although not clear from the documentation, ...
You could configure one of the digital pins as INPUT_PULLUP and connect one end of the switch to it. The other end of the switch goes to ground. LOW = switch ON, HIGH = switch OFF.
const byte pinNumber = 3;
LEDs have a (fairly) fixed voltage drop across them. The red LED is about 2V.
You can use that to work out the voltage at the input. You basically have a voltage divider, with your 200Ω resistor as R1, and your 1kΩ resistor as R2. The voltage drop of the diode is subtracted from Vin.
Vout = (Vin - Vled) * (R2 / (R1 + R2))
= (5 - 2) * (1000 / (...
My guess would be that you're getting noise interference on the line and it's too much for the Arduino's little internal pullup. Try adding an external pullup resistor - say 5k-10k (exact value is not critical).
I notice that your pinMode function calls are not quite correct:
pinMode(Sender = OUTPUT); // Setting pin two to output
pinMode(Reader = INPUT); // Making pin 12 set to read switch data
pinMode(Sender, OUTPUT); // Setting pin two to output
pinMode(Reader, INPUT); // Making pin 12 set to read switch data
Refer to https://www.arduino.cc/en/...
I'd suggest using a multimeter to figure out what's connected to what after hooking up the complete wiring scheme; there aren't that many options and you should be able to figure out what's connected to what soon enough. On a more philosophical note, it's only a bad idea if the alternatives weren't worse.
The expression read3 + " input" performs pointer arithmetic, i.e. you either add 0 or 1 to the start adress of " input", so you get either " input" or "input". Does the leading space disappear when pressing the button?
To correct your code you can print the number separately:
You should get rid of the rest ...
Written and tested. I also included the red blinking led.
const int BUTTON_PIN = 2; // Button
const int in1 = 7;
const int greenLED = 4;
const int redLED = 9;
int buttonPushCounter = 0; // counter for the number of button presses
int buttonState = 0; // current state of the button
int lastButtonState = 0; // previous ...
Actually, you can very easily verify this yourself:
Per item (1602LCD, 7 segment LCD and LEDs check how many pins you need and what type, like e.g. I2C or SPI for the 1602 LCD). The 7 segment displays can have many or less pins, depending on the 'controller', See the reaction of CrossRoads below.
Count them together. If it fits on the Arduino you want to ...
It is wasting of IO pins to use the digital output pin just to get +5V rail. But both options will work. Don't forget to use pull/up or pull/down resistor, or activate internal pull/up resistor on the sensing pin. When the switch will be open, the input pin is not connected anywhere and will act as antenna, so it might pick up some noise.
There are some GNU extensions available in the avr-gcc/avr-g++ compilers (used in Arduino IDE for AVR based Arduino boards). One of them is suport of ... for the case:
case 10 ... 100: Serial.println(F("First")); break;
case 101 ... 1000: Serial.println(F("Second")); break;
Replace the line:
byte alrmSet = map(alrmSwState, 0, 1023, 0, 2);
byte alrmSet = alrmSwState / ((1023 / 3) + 1);
And this should do what you want. Note that in C fractional results are truncated (not rounded)
If you want to declare multiple variables with the same name inside different case statements, you can enclose the code inside each of them inside curly braces:
The curly braces will set the limits for the variables scope to just this case.
There are different ways to accomplish the same thing.
The condition is a flag, or a read port.
// Your first code here.
// second code
Switch contacts will bounce when opening or closing. You may want to consider that. Usually it is stable within 10 milliseconds. Depending on what you ...
There's certainly an issue with your optocoupler circuit aside from the fluctuation you observe.
During a negative half-wave of 220V, you expect D1 to block the current through the LED. However, 1N4007 as any power rectifier has significant leakage current, about 5μA at normal temperature and up to 50μA when the diode is hot. This current will go though the ...
Yes, that is too simple.
The Arduino's IO pin is not designed to directly drive a relay. It needs to go through a transistor first, and you must include a diode to absorb the back-EMF generated by the collapsing magnetic field.
Google for "Arduino Relay" and you will find hundreds of thousands of examples.
In short, the circuit you need to create is this:
One big problem is that you forgot the break statements for those cases. So if it compares in the first one and finds it, you'll still get null because it is going to go look for the third one afterwards.
This answer is based on a previous version of the question
Not necessarily. You can use the internal pullups of the arduino if you're willing to accept that reading a "1" means that no piece is there and reading a "0" means a piece is there.
Connect each wire up to a pin on the arduino. If you do it wisely, step 3 becomes fairly easy.
You need to configure ...
You can use a 5V Solid-State Relay module to control light bulbs. They cost $4-6 from US-based suppliers and $1-3 from a Chinese supplier. Just hook up the supply to the center pin and the load to either the NO or NC pin. Supply 5V to the module and wire a digital pin to the module to control it.
I've just bought a few STP16NF06L fets for this very purpose, N channel MOSFET.
The key part of that part number is the L at the end. This indicates low (or Logic) gate threshold, which means it will switch on fully at 5v gate drive, unlike most fets which are sort of conducting at 5v but need 10v to reach their specification (like an IRF530N).
The 16 and ...
Call the resistors R1 and R2, the negative terminal Ground, and the positive terminal V+. The junction of R1 and R2 is connected to Ground. This holds the resistor ends at the junction to zero volts relative to ground. Ignoring P2 for the moment, the other end of R2 is open circuit to V+ when S2 is open. Applying Ohm's law, we have a finite resistance in ...
I think that the best solution for you, unless you want a simple on/off control (if you want it just go with Majenko's solution) is to use port expanders.
Maybe this can be slightly overkill, but you can think of using a MAX7313.
This IC is I2C controlled and has 16 I/O; you can configure each as input or output, and with automatic PWM generation too. This ...
Switching power on and off to hard drives is not as simple as you may think.
First you have three voltages to control - 3.3V, 5V and 12V, and on top of that you have (ideally) pre-charging for the 5V and 12V pins. The power-on sequence would ideally be:
Power up 5V and 12V pre-charge
Power up 3.3V, 5V and 12V main power
That's 5 poles for one drive (...
Although it looks like 4 pins it's actually 2. You can see that they are connected together in pairs. This is identical to any other tactile switch of the kind used in many Arduino demos and examples.
All you need is some way of connecting the left pair of pins to the right pair of pins (in the underside image). The right pair are ground (you can tell ...
DISCLAIMER: I haven't tested the code in this answer, but I hope there are no problems.
Your code has a major problem: what happens when one gate is moving and you trigger another movement? (reply: something bad). This design issue can be solved by using a standard way of designing these kind of state machine.
In your case a small state machine is what ...
A relay is just an electromagnet, and the same circuit that can drive a relay can drive an electromagnet. You just need to make sure it can handle the power.
The simplest circuit is to use an N-channel MOSFET:
simulate this circuit – Schematic created using CircuitLab
Just make sure that the MOSFET can handle the required power dissipation and ...