New answers tagged pins
1
If the provided source is cut down to the lines that have to do with the temperature, it is just this. If you try this sketch it should behave equally "wrong":
const int sensor = A5;
int tempc;
float vout;
void setup()
{
vout = analogRead(sensor);
pinMode(sensor, INPUT);
}
void loop()
{
lcd.print(tempc);
tempc = (vout * 500) / 1023;
}
In ...
0
Why do you compute tempc only after you print out the value in serialOutputWhenBeatHappens`? You also forgot to read the temperature continuously.
Here is how I would do it:
void loop()
{
// read the sensor before it is printed on the LCD
vout = analogRead( sensor );
// here I'm not sure what you are computing
// you map the sensor voltage to ...
1
Code seems to lack a repeating update of tempc via
vout =analogRead(sensor);
An alternative might be changing the line for setting tempc to be
tempc=(int) (analogRead(sensor) * 500.0f/1023.0f);
2
Most Arduino boards come with a bootloader of some form. This bootloader may do things with IO pins. However apart from that, no, nothing else happens to any IO pins.
The bootloader may:
Flash pin 13 (built in LED)
Configure and communicate on pins 0/1 (UART)
With no bootloader then absolutely nothing happens on any IO pins.
0
I made an Arduino( Arduino Nano) circuit to power a 12V Peltier(which is also a high power source.) using a MTP3055V MOSFET 60V 12A transistor. And the circuit is operating very well.
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