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Use this tag for questions about selecting, connecting, using, and debugging sensors.

3
votes
If the paper is hot when it comes out of the printer, possibly. Could be unreliable though. Better would be to place a photo-interrupter (or IR LED and IR Photodiode) in the path of the paper to det …
answered Jul 2 '15 by Majenko
3
votes
Yes, you do need it. The purpose of the TRIG pin is to cause the module to send out a "Ping". It's what makes the whole thing work. As soon as the TRIG pin goes HIGH then LOW (for a period of not l …
answered Jun 14 '15 by Majenko
1
vote
No. No, you can't. All they sense is the "time of flight". The closest you would come would be to have a sensor which can detect physical properties of the target. That could be colour, sound absorp …
answered Oct 28 '18 by Majenko
1
vote
The green board is an ITG-3500 (3 axis gyroscope) evaluation board of some form. The blue board is some form of microcontroller evaluation board. It probably has one of the Atmel SAM chips on it sinc …
answered Feb 3 '16 by Majenko
1
vote
There's one part of your code conspicuous by its absence: pingRange(2); pingRange(3); You're calling the functions, but you're not doing anything with the returned value. I think you meant to prin …
answered Nov 30 '15 by Majenko
1
vote
The second trace looks like a pulse to me. With that kind of sensor you don't get the PQRST traces of an ECG - just a slight bump when you get a pulse.
answered Nov 25 '17 by Majenko
1
vote
Grab yourself something like this Butcher it to get inside it, and add three small magnets to the fins (should be simple enough - just keep it balanced). Then glue it all back together again. Add …
answered May 29 '15 by Majenko
1
vote
Technically, yes it is possible. Write an app for your phone that scans your fingerprint and does "something" with it. Decide on (and implement) some form of communication protocol between the phone …
answered Sep 1 '18 by Majenko
1
vote
Using the internal pullup resistors for I2C is not recommended. Arduino are very wrong in providing those as the default option and basically "hiding" the fact that I2C needs decent pullup resistors …
answered Dec 10 '15 by Majenko
1
vote
Your second print section will always fail. You have: if(millis() - printTime > printInterval) //Every 800 milliseconds, print a numerical, convert the state of the LED indicator However, a bit …
answered May 23 '16 by Majenko
1
vote
Your problem is in how you are working with the two sensors. At the moment you are triggering both sensors together then waiting for the first one to echo back. Only when that has responded do you … sensors completely separately. Trigger the first, then get the response. Then trigger the second and get the response. …
answered Dec 11 '15 by Majenko
1
vote
Another option (similar to reed switches) is to do it optically. The vane is on an axle. The axle has a disc attached to it. The disc has a small notch out of the edge. Positioned around the edge ar …
answered Oct 26 '16 by Majenko
2
votes
Count is a local variable - it gets re-created afresh every time the loop() runs. Either make it global, or make it static. These two options look like this: Global long count = 0; void loop() { …
answered Jun 24 '15 by Majenko
1
vote
add a second that works in a different way. If both of them agree that there is someone in the shower (i.e., the sensors correlate) then the probability that there is actually someone in the shower is … considerably higher. The great thing about a shower is you are working in a defined enclosed space. That makes it much easier and there are plenty of sensors which, when combined with others, would be …
answered Jun 27 '16 by Majenko
3
votes
You can't. Mobile phone signals don't respect artificial boundaries like a room's walls. You can detect the mobile phone signal from the local cell, but you can't narrow it down to "what is talking …
answered Aug 28 '15 by Majenko

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