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First, please be patient, I'm not electronical person. I am learning Arduino and electronics for hobby and this is my fist time with integrated circuits.

  • Situation: I'm want to extend the Arduino Nano pins (De/Multiplexer) and keep the state (High/Low) of the new pins until I decide to change it again. For keep the states I think that D-type Flipflop memory-based system can help .
  • Question 1: On this system can I change only one bit with a unique signal or need to set all bit states ?
  • Example (reference image):
  1. Memory, previous state: Q0=0, Q1=1, Q2=1, Q3=0
  2. Arduino: Set pin17 (D2) to High -> Memory: Waiting new data.
  3. Arduino: Set pin16 (D3) to High -> Mux: Pass the value to memory at D0
  4. Memory: Read 1 on D0 (this is my doubt. D1, D2 and D3 don't matter ?)
  5. Arduino: Set pin17 (D2) to LOW -> Memory: Save new data
  6. Memory, new state: Q0=1, Q1=1, Q2=1, Q3=0 ? or Q0=1, Q1=0, Q2=0, Q3=0 ?

Question 2: Are this correct ? Question 3: Are there a more efficient way to do this?

enter image description here

Notes:

  • I used a simulator to diagramed the memory based on this datasheet: https://pdf1.alldatasheet.com/datasheet-pdf/view/8337/NSC/74273.html It seems that it is possible, but I want to be sure.
  • My currently solution is use separated flipflops, but I want to simplify it.
  • Connections on reference image are simplified.
  • Sorry about the poor diagram, I don't know programs for beautiful electronical diagrams.
  • Sorry about typos, not-native English person here.
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  • 1
    I don't want to answer in a comment, but have you heard of the 74HC595 chip? That lets you set up 8 outputs using only 3 pins from the Arduino, and they can be chained. That looks simpler than your proposal.
    – Nick Gammon ♦
    Sep 9, 2021 at 6:41
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    Or if you want even fewer outputs used you could consider an I2C IO expander like the MPC23017.
    – Majenko ♦
    Sep 9, 2021 at 8:42
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    feeding demux into the latch will not let you set output pins to various states
    – jsotola
    Sep 9, 2021 at 14:11
  • There is a simple and cheap component that can do what you want, the 74HC259 addressable latch. Essentially it's demux and an 8-bit latch in which the bits are individually addressable.
    – StarCat
    Sep 9, 2021 at 15:12
  • Look at the data sheet of the '273: You cannot set its flip-flops individually. All or none, that's it. Use another IC.
    – the busybee
    Sep 10, 2021 at 6:16

1 Answer 1

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Question 1 and Question 2: I was wrong, this is not the correct way. @jsotola and @the_busybee, thanks for the clarification

Question 3: @Nick_Gammon and @Majenko I think you are right, using i2c are more efficient ways to do. But, the @StarCat proposal is more compatible with my current solution. 74hc259 allows me set the state one by one and keep it until I change it again.

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