I have a list of set-ups and I only have 2 rows in the lcd , I'm trying to scroll down for the moment and I'm doing this by changing the row in the setcursor function to either 0 or 1.
However since that I'll be having about 10 set-ups I used an equation that will change the rows to 0 and one for the ones I want to display and a negative number for those that I don't want to appear. The problem is when setting the cursor's row to -1 or 2, it will ignore the one with row one (which is the 2nd row).
Is there a way that I can overcome this problem ? by setting it to a row that will not appear on my LCD?
I'm using #include <LiquidCrystal.h>
and I already set lcd.begin(16, 2);
int colom[5] = {
0-goDown,1-goDown,2-goDown,3-goDown,4-goDown };
for (int i = 0; i < 4; i++) {
if (colom[i] > 1) colom[i] = -1;
}
lcd.setCursor(0, colom[0]);
lcd.print("choise 1 ");
lcd.setCursor(0, colom[1]);
lcd.print("choise 2 ");
lcd.setCursor(0, colom[2]);
lcd.print("choise 3 ");
lcd.setCursor(0, colom[3]);
lcd.print("choise 4 ");
lcd.setCursor(0, colom[4]);
lcd.print("choise 5 ");
So here goDown is 0 so choice 1 and 2 should appear, but I'm only getting choice 1 and in the second row it's changing quickly between 2 and 5, it's not constant.
I thought about doing an if condition for each choice but that will be a lot of code to write and it won't be efficient for my application.