I'm working on an ESP8266 module that needs to fetch date data from worldtimeapi, everything works fine but the problem is How do I strip of the time field off the datetime JSON response without loop.

Note: Arduino JSON library was used in deserializing the response data and it seems the library only supports char data type.

void loop ()
  // Initialize the request object
  HTTPClient request;
// Make a http request

  // Check the request status code.
int  responseCode = request.GET(); //Get the api host response code.
  Serial.print("Response code is: ");
  if (responseCode == 200); // If the server returned OK
      String responseData = request.getString();
      Serial.println("Response from the server is:");
        // Deserialize the JSON response data
       StaticJsonDocument<715> result; // Declare data storage to stack
      //Check for error during data deserialization
      DeserializationError error = deserializeJson(result, responseData);
      if (error) 
        Serial.print(F("Response deserialization failed with reason: "));

        char abbreviation = result["abbreviation"];  // Returns the current time zone abbreviation
        char timezone = result["timezone"]; // Returns the current time zone 
        char datetime = result["datetime"]; // "2021-03-12T17:04:0
        char date = datetime.remove(9,22); // This line throws error : request for member 'remove' in 'datetime', which is of non-class type 'char'

        Serial.print("Current time is ");
        Serial.print(" ");
        Serial.print(" "); 

  • why without loop?
    – jsotola
    Commented Mar 13, 2021 at 20:05

1 Answer 1


You can use strtok to split the string on the T character:

char *datepart = strtok(datetime, "T");
char *timepart = strtok(NULL, "T");

Serial.print("The current date is: ");
Serial.print("The current time is: ");

An alternative is to just find the T and turn it into the NULL terminating character:

char *T = strchr(datetime, 'T');
*T = 0;

If you need to copy the string data into a temporary string first you can do:

char temp[strlen(datetime)+1];
strcpy(temp, datetime);

Then operate on temp instead of datetime.

  • I need to get rid of T17:04:0.
    – Ruby
    Commented Mar 13, 2021 at 20:04
  • Then just use datepart.
    – Majenko
    Commented Mar 13, 2021 at 20:06
  • How do I do that in C++, I think datepart is a SQL syntax.
    – Ruby
    Commented Mar 13, 2021 at 20:14
  • I have shown you how to do it.
    – Majenko
    Commented Mar 13, 2021 at 20:14
  • 1
    You may need to copy the string content to a temporary work string first then.
    – Majenko
    Commented Mar 13, 2021 at 20:23

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.