I want to battery-power my NodeMCU. It will be mostly deep sleeping and waking up every 1-2 minutes.
I've seen the best way to power it with the least wasting of power is through a lithium battery.
So I've bought a 18650 rechargable battery and a MCP1700 LDO which will give me a constant 3.3 V, that will connect straight to the 3.3 V pin and bypass the NodeMCU's regulators, as I understand from here.
My question is: if all of the previous is correct, what will happen when the 18650 battery power fall below the 3.5 V (3.3 V + 0.2 V from MCP1700 dropout)? Will it stop automatically giving power at all? Will it provide less than 3.3 V and will it harm the NodeMCU?