I am looking for a way to increment a variable by one each time a button is pressed. Current approach is the following :

    if (redButton.isPressed())

isPressed() just return true if the pin state is HIGH.

delay(100) is used to compensate the small amount of time the button is being pressed. Otherwise a would be incremented multiple times in a single press. But it's blocking behavior, my program can't do anything else during that delay.

In short I'm looking to add a method in my Button class to detect if the button "has just been released".


1 Answer 1


In your approach a button press will be detected every 100ms when you just keep the button pressed. So you have to set a flag when the button is pressed. When the button is not pressed while your flag is set, that's the event you're looking for. In this way you can detect both a button press and a release respectively. As @JRobert mentioned, there still has to be an amount of time between two calls to such a routine to provide some button debouncing.

bool pressed_flag=false;
bool button_timestamp=millis();
uint16_t button_period=100;

  if(redButton.isPressed() && !pressed_flag){
    // button has just been pressed
    // you can do sth. here
  else if(!redButton.isPressed() && pressed_flag){
    // button has just been released
    // you can do sth. here
  • Also use either a timer library, or hand-code with millis(), to come back and check the button after a time. That interval defends against contact chatter or bounce (multiple inputs for a single press). Using the flag prevents you "detecting" one long button press multiple times. And your code will still not get blocked.
    – JRobert
    Aug 9, 2019 at 14:13
  • @JRobert theoratically my code is allready non-blocking. But I aggree: it doesn't include any debouncing and my routine should only be called in a specific period.
    – Sim Son
    Aug 9, 2019 at 14:16
  • Agreed - it doesn't block. I just intended to suggest the addition of chatter removal to your already appropriate solution. (And I got caught accidentally submitting a partially-edited comment! ):
    – JRobert
    Aug 9, 2019 at 14:18
  • @JRobert you're absolutely right, I added what you suggested!
    – Sim Son
    Aug 9, 2019 at 14:23

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