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I designed a PWS (personal weather station) which will be placed in a difficult to access location. In case of the master crashing and not requesting from the slave for a certain amount of time (stay alive protocol), is it possible to reset the master from the slave by powering a digital pin?

enter image description here

Note, I improvised a pull down circuit so that the Arduino Nano's D7 (or any other digital pin) 5V output could be pulled down to 3.3V.

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    for me it didn't work for Wemos D1 mini. with level shifter it worked. I don't know why. but you should have a level shifter for esp8266 RX too
    – Juraj ♦
    Jul 26, 2019 at 15:18
  • care to elaborate into an answer? tks @Juraj
    – tony gil
    Jul 26, 2019 at 15:57
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    I plan esp-01S wiring experiments this weekend and the reset of the esp8266 from Arduino is one of the goals
    – Juraj ♦
    Jul 27, 2019 at 6:17
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    The "RST" (reset pin) should work, try it w/o the other device, to see if it actually resets.
    – Paul
    Jul 27, 2019 at 7:12
  • @Juraj da man! tell me how that goes, please! Do you want me to post this fritzing diagram as an fzz somewhere?
    – tony gil
    Jul 27, 2019 at 8:55

2 Answers 2

Reset to default
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There is no need for a voltage divider or a level conversion on the reset pin of the esp8266. The esp8266 has internal pull-up on reset pin. To reset the esp8266 the reset pin must be connected to ground for a very short moment.

To pull the reset pin LOW with pin of the other MCU we do:

void resetEsp() {
  pinMode(ESP_RESET_PIN, OUTPUT);
  delay(1);
  pinMode(ESP_RESET_PIN, INPUT);
}

ESP_RESET_PIN is the pin wired to reset pin of the esp8266. It is not configured in setup() and it is never set HIGH (we don't want to send 5 V to esp8266). Setting the ESP_RESET_PIN to OUTPUT connects it to ground, setting it back to INPUT hands the control of the line back to esp8266 reset pin's internal pull-up.

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  • not sure i understand the wiring. Does that mean that my Arduino (MCU) digital out is connected directly to NodeMCU RST pin? If not, do you mind posting a Fritzing diagram? UPVOTED pending clarification for eventual ACCEPT AS CORRECT ANSWER.
    – tony gil
    Jul 29, 2019 at 17:36
  • i am posting a Fritzing as an answer, please comment if correct or incorrect. Vote (up or down) if you will.
    – tony gil
    Jul 29, 2019 at 17:43
  • yes direct connection, because there is never 5 V from Nano side. it only pulls the reset LOW
    – Juraj ♦
    Jul 29, 2019 at 18:13
  • ACCEPTED, tks!!
    – tony gil
    Jul 30, 2019 at 15:49
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As per verification from Juraj, this would be correct wiring for his answer:

enter image description here

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  • the point of reset from other MCU is not in wiring, but in code.
    – Juraj ♦
    Jul 29, 2019 at 18:11
  • so is my original diagram correct, with the voltage divider?
    – tony gil
    Jul 29, 2019 at 18:25
  • I removed my comments about level conversion on I2C following Majenko's explanation here: arduino.stackexchange.com/questions/67461/…
    – Juraj ♦
    Jul 30, 2019 at 9:11
  • as I write in the answer you don't need voltage divider on reset because it has nothing to divide. there is never 5 V
    – Juraj ♦
    Jul 30, 2019 at 9:12
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    yes. of course there is a risk that some other unintentionally to Nano uploaded sketch sets the pin as output high.
    – Juraj ♦
    Jul 30, 2019 at 9:34

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