1

I have a class named timeOut dealing with timeout tasks.

I'm to write a sketch, common for Sonoff basic and Sonoff Dual, meaning that I may have 1 task for Basic and 2 tasks for Dual.

Declaring instances looks like:

timeOUT timeOut_SW0("SW0",TIMEOUT_SW0);
timeOUT timeOut_SW0("SW1",TIMEOUT_SW1);

for code simplicity I'd rather create an array of references and call it using a for loop:

timeOUT TO[]={timeOut_SW0,timeOut_SW1};

is it the right way to call it as a reference ?

3

You can't. The C++ language doesn't support arrays of references. You have the choice to either create an array of objects:

timeOUT TO[] = {timeOUT("SW0",TIMEOUT_SW0), timeOUT("SW1",TIMEOUT_SW1);}

or an array of pointers:

timeOUT *TO[] = { &timeOut_SW0, &timeOut_SW1 };
  • timeout_Switch:243:34: error: request for member 'remain' in 'TO[i]', which is of pointer type 'timeOUT*' (maybe you meant to use '->' ?) if(TO[i].remain()>0) { ^ – Guy . D Jul 17 at 19:44
  • I upvoted this answer, and going to delete mine since it's wrong. – Michel Keijzers Jul 17 at 19:44
  • I chose 2nd option you offered – Guy . D Jul 17 at 19:46

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