That is a 3.3V device. you'll need to give it a separate 3.3V power input, and it needs much higher current at 3.3V than the Arduino can supply.
I don't know if you can feed it a 5V logic signal or not. (If it needs 3.3 V control signals as well, and it's current needs are modest you could step down the voltage from an Arduino 5V digital output to 3.3 with a simple voltage divider circuit.)
You'd be better off getting a 5V relay. If you do a Google search on "Arduino Relay" you'll find tons of them. You can get 1 relay, 2 relay, 4 relay, and more on a board. Many have optical isolation to make sure the relay coils don't add noise to the logic lines.
In general it's a good idea to use a separate power supply for the relay, or at least use a power supply with plenty of current to spare, and add filtering capacitors between the 5V rail and ground right next to both the relay and the Arduino. These capacitors serve to filter out variations in voltage as the relay coils are powered on and off.
(Even "digital" relays draw a large amount of current from their power source when they first turn on, and abruptly stop drawing current when they turn off, which introduces a lot of noise on the power line. "Naked" relays need "flyback diodes" to avoid reverse currents that will destroy transistors, but the "digital ready" relays I'm talking about have those built in.)
Here is one such relay I found from Googling "Arduino relay".