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I'm looking for a Normally-Open optocoupler board for arduino. I need to control power of a device (DC 12v, 500mA). I tried to use TLP281 board, which works, except that it inverts the output: device is powered when there is no control signal (i.e., it is Normally-Closed).

For this reason, the TLP281 board is not useful in my project.

This is picture and schematics for TLP281 board:

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I need an optoisolator board which works analogous to normally open mechanical relay: when there is no signal, device must not be powered; and when there is signal, device must be powered.

NOTE: workaround by inverting the control signal in microcontroller firmware is not permitted, as the device must not be powered when microcontroller is off

  • @JaromandaX Do you know a schematic which explains how to create Normally-Open relay based on TLP281 (or any other opto-isolator)? – Igor Liferenko Feb 27 '19 at 3:06
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    @JaromandaX I tested it and I can say for sure that this board inverts the signal (on low input, there is power on output, on high input, there is no power on output). – Igor Liferenko Feb 27 '19 at 5:32
  • I think every driver does what you want, only this one has it inverted. What is the device? A motor? Do you need pwm to control the speed? This could be a normal driver: aliexpress.com/store/product/… There are similar modules for 4 and 8 channels. – Jot Feb 27 '19 at 6:10
  • @Jot the device is Panasonic KX-TCD245, I need just to turn it on or off. – Igor Liferenko Feb 27 '19 at 7:25
  • @JaromandaX the links that you give are for the same board which is in OP - it is Normally-Closed - I need Normally-Open – Igor Liferenko Feb 27 '19 at 7:27
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I don't think there is a need for a specific "normally-open" opto-coupler. Same result can be easily achieved by using "normally-closed" opto-coupler and making a slightly modified "NOT" logic gate using three resistors and NPN transistor.

NOT gate design

1. When INPUT is LOW:

Base of Q1 is shorted to ground through R1 so Q1 not letting the magic pixies go through. This makes OUTPUT show 5V and be in HIGH logic state.

2. When INPUT is HIGH:

Base of Q1 is powered by voltage divider R/R1. R needs to be much lower than R1 to keep Q1 saturated. This makes Q1 to be passing current and setting OUTPUT to LOW state by creating a voltage divider R2/Q1(collector-emitter resistance) This means that value of R2 should be much higher then c-e resistance of Q1.

3. When INPUT is floating (microcontroller is turned off):

Any voltage on INPUT caused by imperfections of the hardware, E-M noise induction, static electricity, etc. should be discharged to ground by resistors R+R1 keeping INPUT in LOW state. (This means that R+R1 cannot have to high value or the discharge speed might be to slow)

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  • There is a problem with your solution: microcontroller is powered from USB, so the "5V" in your scheme will not be there when microcontroller is off. Thus, changes must be made to "output" side of optocoupler, not to "input" side. – Igor Liferenko Feb 28 '19 at 3:32
  • If you use tougher npn transistor (for example the same one as uour opro-coupler) and higher resistor values (similar values as your opto-coupler) you can use this with 12V power source. You can remove R1 then because right side is never floating. – Filip Franik Feb 28 '19 at 8:55
  • If I understand you correctly, you are suggesting something like this, right? ti.com/lit/ds/symlink/uln2003a.pdf – Igor Liferenko Mar 1 '19 at 6:34
  • Actually I was suggesting that you simply get S8050 transistors (100 for 1 USD) and 5.1K resistors (100 for 0.70USD) and make a NOT gate with identical load bearing properties to the opto-coupler you shown. I assumed that you use that opto to steer a MOSFET since anything spiking above 500mA could burn it anyway (S8050 used in opto is rated for max 500mA) – Filip Franik Mar 1 '19 at 8:32

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