My code: https://pastebin.com/UmdK33U2

I made a menu so I can send commands. First I connect to the wifi and then I send the command to send a request.

Then when it detects the key datos(); goes true, so the loop detects that and it starts sending requests. After 2 requests it just doesnt continue.

What I can do?

Btw im using a ESP32.

Thank you!

boolean datos = false;

#include <WiFi.h>
#include <HTTPClient.h>

const char* ssid = "ssid";
const char* password = "pass";

//removed the password and ssid for security, it was there before.
void setup() {
  pinMode(2, OUTPUT);

  while (!Serial)
  Serial.println("Welcome to the menu, choose what do you want to do:");
  Serial.println("1º Connect to the Wifi | W");
  Serial.println("2º Scan Wifi | S");
  Serial.println("3º Send data to Website | D");
  Serial.println("Made by Francine and Javi.");

void scanwifi() {
  int n = WiFi.scanNetworks();
  Serial.println("Scan have been finished.");
  if (n == 0) {
    Serial.println("No networks have been found.");
  } else {
    Serial.print(n); // imprimir en el puerto serial el # de redes encontradas
    Serial.println(" networks have been found.");
    for (int i = 0; i < n; ++i) {
      // SSID: Nombre de la red; RSSI: Potencia de la red en dBm
      Serial.print(i + 1); //iniciamos en la red # 1...
      Serial.print(": ");
      Serial.print(WiFi.SSID(i)); //Imprime el nombre de la red
      Serial.print(" (");
      Serial.print(WiFi.RSSI(i)); //Imprime la potencia de la señal en dBm
      byte encryption = WiFi.encryptionType(i); // en la variable encryption, guardamos el tipo de encriptación de la red
      Serial.print(" Encryption Type: ");
      Serial.println(encryption, HEX); // imprimimos el tipo de encriptación: 2: WPA, 5: WEP, etc. 

void conectarsealwifi() {

  WiFi.begin(ssid, password);

  while (WiFi.status() != WL_CONNECTED) {

    Serial.println("Connecting to WiFi..");

  Serial.println("Connected to the WiFi network");

void loop() {
  if (Serial.available()) {
    char ch = Serial.read();
    if (ch == 'w' || ch == 'W') {
    if (ch == 'S' || ch == 's') {
    if (ch == 'd' || ch == 'D') {
      datos = true;
    if (datos == true) { // si esta habilitado el sending de datos haz
      //randomN = random(200);
      if (WiFi.status() == WL_CONNECTED) {
        digitalWrite(2, HIGH);
        HTTPClient http;

        http.begin("removedtheurl"); //Specify the URL
        int httpCode = http.GET();                            //Make the request

        if (httpCode > 0) { //Check for the returning code

          String payload = http.getString();

        } else {
              "Error on HTTP request, reminder maybe its cloudflare shit.");
        http.end(); //Free the resources
        digitalWrite(2, LOW);

    } else {

  • If you fix your indenting you'll soon find your problem. – Majenko Dec 1 '18 at 17:04
  • @Majenko Hi, thank you for responding. I dont understand your response, im not a foreign speaker, mind explaining better the solution to my problem? – unknown Javi Dec 1 '18 at 17:11
  • The basic layout (indenting) of your program is a mess. If you fix that and lay it out properly you will be able to follow the flow of your program better, and the reason for its behaviour will become apparant. – Majenko Dec 1 '18 at 17:13
  • @Majenko What I checked is that if I type nothing and I send it the loops continues for 1 row then bakc to normal. – unknown Javi Dec 1 '18 at 17:36
  • I know. I can see that by just looking at the flow of your program (after fixing the indenting). If you don't know how to indent properly then please use the auto-format facility in the IDE to do it for you. – Majenko Dec 1 '18 at 17:39

You send from Serial Monitor a character followed by a new line character. This two characters are available. Nothing more to enter the if (Serial.available()) { block.

| improve this answer | |
  • Thank you for your response. How can I apply it on my code? – unknown Javi Dec 1 '18 at 17:50
  • by moving the if (datos) { block out of if (Serial.available()) { block? – Juraj Dec 1 '18 at 17:53
  • Thank you, it is working. Have a good day. – unknown Javi Dec 1 '18 at 18:16

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