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Especially on ESP32*/8266, when you select debug (debug/release) : as a target, VisualMicro detect it and start the simple debugger (without JTAG).

Do you know if when target is debug, is there a #define created somewhere by VS that could be use with #ifdef for example?

*ESP32 WROOM not ESP32 WROVER able to debug through USB double chanel

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  • the documentation for visual micro is here. the relevant section is "defines" about halfway down the page. – Link0352 Apr 13 '18 at 16:59
  • Ok but strange behaviour, need to be tested... – E.Racineux Apr 13 '18 at 17:55
  • _DEBUG is define by VMicro in project parameter for each target with Define _DEBUG Constant set to 1 (0 by default) [![enter image description here][1]][1] [1]: i.stack.imgur.com/YriDg.png – E.Racineux Apr 13 '18 at 18:26
  • Visual studio Debug/release compilation target switch has no effect during compilation but affect intellisense #ifdef _DEBUG is grayed or not. So it is not easy to follow the real compile target. I suggest to set Define _DEBUG Constant to 1 in VS 'debug' compilation target project configuration and compilation will follow intellisense. But: Another source [here][1] [1]: visualmicro.com/forums/YaBB.pl?num=1441308470 – E.Racineux Apr 13 '18 at 18:26
  • Another advise, clean the compiled file because VS doesn't detect Define _DEBUG Constant like another "standard" #define and your .cpp affected are not recompiled. – E.Racineux Apr 13 '18 at 18:26

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