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I am trying to learn how to make a shift register work. I have been working off of the Arduino ShiftOut tutorial.

My issue is that the shift register isn't working when the circuit is powered and I am not sure what is wrong. I suspect the issue is with pins 10-13 on the 74HC595?

I have done this with an actual board and the 123d.circuits.io simulator with the same result:

http://123d.circuits.io/circuits/444111-shift-register

enter image description here

The code is very simple and taken from the tutorial:

// SH_CP; 11
const int clockPin = 9;
// DS; 15
const int dataPin = 8;
// ST_CP; 12
const int latchPin = 10;

void setup() {
  pinMode(clockPin, OUTPUT);
  pinMode(dataPin, OUTPUT);
  pinMode(latchPin, OUTPUT);

  Serial.begin(9600);
  Serial.println("reset");
}

void loop() {
  for (int number = 0; number < 256; number++) {
    Serial.println(number);
    digitalWrite(latchPin, LOW);
    shiftOut(dataPin, clockPin, MSBFIRST, number);
    digitalWrite(latchPin, HIGH);
    delay(500);
  }
}
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    Why is GND (also) connected to Q0? Idem for STCP? You also need to swap the wires going to pins 11 and 12 on the chip. – Gerben Nov 18 '14 at 19:23
  • @Gerben good catch that was a mistake. see answer below for the other half of the fix – Charles Wesley Nov 18 '14 at 19:47
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Solution: Remove ground from Q0 as Gerben correctly pointed out in comments.

Also: rotate LEDs 90 degrees so that the anode and cathode are on different rows.

What was tripping me up is in the Arduino tutorial diagram is a little unclear on this (I now understand why their way is correct and my way (in the question) was wrong:

enter image description here

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