You forgot to add one more character to the array to place a \0 (0 value byte) in. This denotes the end of a string. If you forget this, the string will continue until it finds the first 0 byte, which will probably be after the original string copy. This can be dangerous, because it might be in memory that is not containing useful data, and those weird character can be many if there is not a 0 soon or at all.
Note that the 6 bytes you get are the bytes EXCLUDING this 0 byte, so you need to allocate 7 bytes to store a string of length 6.
Instead of the for loop you can use the strcpy function which copies a function including the 0 string.
See description:
Description
The C library function char *strcpy(char *dest, const char *src) copies the string pointed to, by src to dest.
Declaration
Following is the declaration for strcpy() function.
char *strcpy(char *dest, const char *src)
Parameters
dest − This is the pointer to the destination array where the content is to be copied.
src − This is the string to be copied.
Return Value
This returns a pointer to the destination string dest.
Example
The following example shows the usage of strcpy() function.
#include <stdio.h>
#include <string.h>
int main () {
char src[40];
char dest[100];
memset(dest, '\0', sizeof(dest));
strcpy(src, "This is tutorialspoint.com");
strcpy(dest, src);
printf("Final copied string : %s\n", dest);
return(0);
}