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My circuit is a simple one, I am using an arduino atmega 2560. One 5mm red LED connected in series with a 150 ohm resistor. If I didn't make some kind of goof, a red LED has a voltage drop of 2 volts and operates at 20 ma. So my calculations were, 5-2=3volts. 3V/150=20 mA. So I put a 150 ohm resistor. My code to control it is the following:

int red = 48;

void setup() {
pinMode(OUTPUT,red);    
}

void loop() {    
digitalWrite(red,HIGH);
}

When I run the code the red LED is dimly lit, when connected to the 5V on the board it lights brightly. When I measured the voltage between pin48 and ground I got 1.7 volts. When connected directly to the 5V and GND the voltage between them is 4.95V. Measuring a pin with nothing connected set at HIGH results in a 4.99V reading. Is my board malfunctioning or have I missed something?

  • 1
    It's pinMode(red, OUTPUT) – user31481 Oct 29 '17 at 15:21
1

The pinMode() arguments are backwards. As it is the LED is powered through the input pullup resistor, which is about 20-50kohm.

  • You sir deserve a pizza, thank you so much! I noticed it now, what a dumb mistake :D Well I fixed it now and it works. Cheers again for the help. – Entity5 Oct 29 '17 at 15:06

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