How to connect a simple wall switch to arduino GPIO

Question

I am trying to create a smart doorbell, but my problem is that doorbell makes ring any time when nobody touch the button.

I think that the problem is caused for the incorrect way to connect the analog wall button to arduino GPIO.

Basically my wiring diagram is:

Analog Input (A0) to 1 pin of the button. Ground of the Arduino (GND) to the other pin of the button.

When the button is pressed, the circuit is closed, and doorbell makes ring!

But surely this is not the way to connect a button on the wall because the doorbell sounds on its own.

I leave a picture of the button

Answer 1

jose can u c is absolutely right, you need a pullup. No need to change your wiring however: the Arduino has built-in pullups on all the inputs. You just have to activate them:

const uint8_t buttonPin = A0;  // or any other pin for that matter

void setup()
{
    pinMode(buttonPin, INPUT_PULLUP);
}

Answer 2

You need to have a pull-up resistor, see circuit below.

You do not need to connect it to an Analog pin, but a digital pin. Without a pull-up or pull-down resistor, the voltage on the input pin "floats" anywhere, and can give false triggers. This circuit forces the pin to either be 5V or 0V.

^{simulate this circuit – Schematic created using CircuitLab}