The led strips will have their own current limiting / drivers. A couple of quick calculations:
- 24V at 12W is (I=P/V) 12/24 = 0.5A per meter
- 5 meters = 0.5*5 = 2.5A
So each strip takes 2.5A. The CAT4101 is a 1A max driver, but since it is a constant current driver it's not suitable for a strip that has its own current control built in.
I suspect each meter consists of 10 chains of 6 LEDs with a current limiting resistor or two. Out of interest, calculations:
- 6 LEDs at (say) 3V forward voltage would be 18V.
- 24 - 18 = 6 volts to drop
- 500mA divided by 10 chains = 50mA
- R=V/I = 6 / 0.05 = 120Ω current limiting resistors.
- P=I²R = 0.05²×6 = 300mW dissipated from the resistors.
Instead all you need is an N-channel MOSFET as a low-side switch that can operate with that much current and not dissipate too much heat while switching. The more you derate the MOSFET the less heatsinking it would need.
A quick look on Digikey gave a possible match of PSMN022-30PL - 30V, 30A, 27mΩ (typ) at 4.5V gate voltage.
simulate this circuit – Schematic created using CircuitLab