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I've seen some similar questions here for using MOSFET to control 12V LEDs But apparently the only MOSFET currently available to us is a 2-MOSFET high power trigger module, details in the link below.

https://www.elecrow.com/high-power-mosfet-trigger-switch-drive-module.html

How do we connect this to the Arduino to send the PWM trigger (I get confused by the three holes) and how do we connect the DC power to this??? I get confused with the power connections.

  • Did the picture with labels that tell you what connects where not help you? – Majenko Feb 25 '17 at 10:09
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The three TRIG/PWM pins are connected to the same electrical point. The same goes for the three GND pins.

You can either solder:

  1. A 2-pin 0.2 inch screw terminal (the very same kind of those blue connectors already in the board) to the pair of big holes closer to the edge, or
  2. A 2-pin 0.1 inch header to the 2 holes in the centre of the 4-hole row (the smaller ones). 2-pin header

These will be the control input you should be connecting your Arduino to.

The DC power supply for the load that will be switched by the MOSFETS has to be connected between the VIN+ and VIN- terminals. Note that VIN- is connected internally to GND.

Your load has to be connected between the OUT+ and OUT- terminals.

That's all you need to know. In case you're in doubt, I've drawn this schematic for you (see below)

schematic

simulate this circuit – Schematic created using CircuitLab

IMPORTANT ADDITIONAL NOTES:

  1. No flyback diodes are present in the board. If you try to switch an inductive load (a motor, a solenoid, etc.) with this board you have a high risk of damaging the MOSFETs and rend it useless.

  2. You need at least a 5V control signal for switching high current loads with this board. Although a 3.3V control may seem able to switch the MOSFET, its internal RdsON at 3.3V could easily be high enough to produce excessive power dissipation and blow up the MOSFET. See these curves from the AOD4184 datasheet:

ON-region characteristics ON-resistance vs. Vgs

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it seems to be a typical low-side switch (dual switches). the load goes into DC+ and DC- --> ask the manufactuer to be sure.

whether it works for you will depend on the load, driving signal and the mosfet used -> you should ask the seller for a schematic, or buy one and reverse engineer it.

  • 1
    I'm afraid that's wrong. – Enric Blanco Feb 25 '17 at 13:05

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