What is the opposite of this data operation?

Question

If I store in an array a double-value in this format, in which format I should be able to read the same double out?

double myDouble = 12.123456;
byte myArray[] = {0x00, 0x00, 0x00, 0x00};

myArray[0] = (myDouble >> 0);
myArray[1] = (myDouble >> 8);
myArray[2] = (myDouble >> 16);
myArray[3] = (myDouble >> 24);

Answer 1

You are better off making a union, that will be compiler independent, and won't give you the (possibly) odd results that trying to shift a double would give.

Example:

  union 
    {
    byte myArray [4];
    double myDouble;
    } foo;


   foo.myArray [0] = Serial.read ();
   foo.myArray [1] = Serial.read ();
   foo.myArray [2] = Serial.read ();
   foo.myArray [3] = Serial.read ();

   double f = foo.myDouble;

Even then be cautious that whatever is sending you this double in 4 bytes is using the same encoding for doubles that the Arduino does. For one thing, double and float are the same on the 8-bit Arduinos (they are only 4 bytes).

Answer 2

in the simplest form (compiler dependent however), a pointer will do.