2

I'm new to Arduino, and I'm trying to connect my Leonardo via WiFi using a ESP8266 module. What I want to know is if I can power it directly from the onboard 3.3V pin like in the image:

Leonardo

Or do I need an external voltage regulator? I don't want to damage it. Thanks!

Improve this question

2 Answers 2

Reset to default
4

The Leonardo is specified to provide only 50mA on the 3V3 pin. A ESP8266 can use up to almost 300mA when transmitting. Consider using a LDO regulator connected to the 5V pin instead.

Improve this answer
6
  • Thanks! And the 5V pin can handle the current?
    – Christian Rodriguez
    Sep 1, 2016 at 16:15
  • If supplying power via USB it should be fine unless you have a few other devices connected to it. If supplying power via an external 7-12V supply then the on-board regulator may get a bit warm, so you'll have to judge from that.
    – Ignacio Vazquez-Abrams
    Sep 1, 2016 at 16:19
  • That specification in wrong. The 3.3v regulator is actually 150mA not 50mA. Don't believe everything you read on the Arduino website.
    – Majenko ♦
    Sep 1, 2016 at 16:28
  • Ok, so which one should I trust? I don't want to find out by testing and killing my brand new Leonardo ;)
    – Christian Rodriguez
    Sep 1, 2016 at 20:28
  • If you're communicating with the ESP8266 for very short bursts then you may be able to get away with the on-board LP2985 if you add a local bulk capacitor. If you need constant communications then you should strongly consider a larger regulator.
    – Ignacio Vazquez-Abrams
    Sep 1, 2016 at 20:47
1

Remeber sometimes Arduino board is not delivering sufficient voltage to the ESP8266 module. You can use a 3.3 V ( Do not exceed input voltage from 3.3v) regulator ( AMS1117 ) to power this module.

Improve this answer
1
  • Actually that's the one I've been using. Aaand, I got rid of the Leonardo. I'm programing the ESP module, avoiding the bottleneck of the slower Leonardo's processor.
    – Christian Rodriguez
    Nov 27, 2017 at 15:47

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.