The first challenge on the Arduino Uno manual is to make a closed circuit with a button and LED. The voltage is provided by the 5V pin (non IO), connected by wire to (+) on the bus (breadboard). The wire connects to a resistor, which makes sense since it resists current running from source. The button connects to the resistor, if pushed, the button closes the circuit and current passes through LED (making it shine) and through a wire to GND.
OK. The second challenge makes no sense. The resistors are connected not to the 5V, but the GND. WHY? Doesn't current dissipate past at ground?? As if the GND is supplying power!? It's like flipping the anode/diode! Here's the challenge: .What is the logic behind connecting the resistors to GND and WHY DOES IT SUPPLY POWER? I'm not talking about the button, which step two somewhat explains but not why, but the LEDs. Thank you thank you thank you!!
EDIT: Ok, then. I am now being told current flows negative to positive. Fine, then why resistor connected to positive? Also, I was told that GND is there to dissipate the energy flowing from positive because some of that energy was lost. Then, could you explain the circuit and whether flow is perpetual or lost at the end (wherever that is) and if it isn't perpetual in a loop, why have a resistor past the LED when the LED recieved all the volts and the electrical energy it then outputs back on the cycle is reduced by the resistor. Thanks.
Also, I'm changing my question to "Why does resistor on GND ever work on LED" to "Why have resistor at end of circuit cycle if GND dissipates final energy?".