1

I have following problem: I'm reading 8 bit signal from one Arduino pin and store all informatin in bool array. Now I want to convert this array to single byte in decimal. How to do this?

I've tried this:

bool ID[8] = {0, 0, 0, 0, 0, 0, 1, 1};
int recivedID = int(ID);

and

bool ID[8] = {0, 0, 0, 0, 0, 0, 1, 1};
int recivedID = ID.toInt();

non works.

1
  • 1
    Why save it in a bool array in the first place? You could make a byte and set each bit individually. That will be more efficient.
    – aaa
    Commented Aug 16, 2016 at 9:16

2 Answers 2

0

try with this:

int recivedID = ID[0] | (ID[1] << 1) | (ID[2] << 2) | (ID[3] << 3) | (ID[4] << 4) | (ID[5] << 5) | (ID[6] << 6) | (ID[7] << 7);

which is the same as

int recivedID = 0;
for(int i=0; i<8; i++){
   recivedID |= ID[i] << i;
}

I haven't tested it though.

0
1
byte BoolArrayToByte(bool boolArray[8])
{
  byte result = 0; 

  for(int i = 0; i < 8; i++)
  {
    if(boolArray[i])
    {
      result = result | (1 << i);
    }
  }

  return result;
}

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.