1

I'm a member of a Formula SAE team and we use the Performance Electronics ECU which uses the CAN protocol with a speed of 250 kbit/s and works fine with our 2D Recording Systems Data logger, but we're trying to build a telemetry system which gathers the same data from the CAN bus using an Arduino Uno and CAN shield provided by SparkFun Electronics.

However the CAN shield we're trying to use has failed to initialise the communication with the bus. Kindly help me out on what can be done or are there any alternatives of communicating using CAN with Arduino?

P.S. The link for the CAN shield: CAN-Bus Shield Hookup Guide

| improve this question | |
  • Have you shecked the shield pins match the ECU connector pins? The shield is configured to match the pins on their OBDII->DB9 cable and may not match the "vanilla" CAN pinout. This will require desoldering jumpers – crasic Feb 18 '16 at 23:33
  • You may also try to add termination to the BUS – crasic Feb 18 '16 at 23:50
  • Hi Crasic, according to the schematic of the shield already has termination resistance to the bus, and regarding the connections, yes the ECU Connector pins match with the shield pins. Our data logger works fine but the shield isn't working. Also could you provide me with the info on ODBII-> DB9 cable and the "Vanilla" CAN Pinout. Thanks – Yashasvi Karnena Feb 20 '16 at 15:15
  • I also forgot to tell that the communication protocol is SAEJ1939 and the Baud rate is 250KBPS – Yashasvi Karnena Feb 28 '16 at 19:41
2

Beware, the industry standard pinout for CAN on DB9 connectors is different to what Sparkfun use on their shield:

Which software have you been using on the Arduino? Any additional info on the ECU you're using, and the wiring in your system?

| improve this answer | |
0

I found this wiki particularly useful: CAN-Bus Shield Wiki

And yes, like CQuinson said, you have to pay attention to the pins used. I know Sparkfun is known for having an issue with which pin the CS pin is assigned to (D9 or D10).

| improve this answer | |

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.