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Lets suppose I have a circuit with a car battery, a switch and a led. The led will turn on when the switch is closed, and turn off if it's not. I want to remove the led from the circuit and put an Arduino in that place to "read" when the circuit is closed or open.

I'm a good programmer, so the code is not the real problem. I only want to know how to do this without damaging the board.

How can I do this?

  • 2
    Lookup voltage dividers. – Gerben Nov 9 '15 at 18:44
  • @Gerben What should be the destination voltage to enter into a digital input pin on the arduino? 5v? – Guilherme Nov 11 '15 at 1:29
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    5v indeed. But I'd leave a bit of margin. – Gerben Nov 11 '15 at 15:50
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As @Gerben says, voltage dividers are a good place to start. To elaborate on the topic, you can use a combination of voltage dividers, zener diodes and clamping diodes.

This EE.SE post has some good info about this, related to ADC, but still the same.

First off, a voltage divider circuit is easily found on the internet,

  1. Google
  2. Wikipedia

This circuit from Hyperphysics shows the basics: Hyperphysics


To add more protection to this so as not to go over the max I/O voltage of the MCU, you can add a zener diode on the Vout. That would give you something like this(Olins):

credit to Olin

This will give you the desired range to give legitimate High and Low on an I/O.


If you wanted to forgo the voltage divider and zener you can use clamping diodes to the microcontroller supply voltage Vcc. This will give a range that will not damage the I/O.

schematic

simulate this circuit – Schematic created using CircuitLab

The 10k resistor is there to limit the current through the diodes, which are Schottky diodes.


Another method, which I have used before and is reliable, is to use a diode and two resistors like below:

enter image description here

The logic is that, when the input IN is > Vcc(5V) the signal on the I/O _IN will be the voltage of the pull_up resistor R2, if it is low or floating the signal will be low. R1 also gives a known logic state if the input floats.

Edit: Changed the image to proper logic flow.

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    Be careful that the IN and _IN pins in the last circuit are "logically" swapped, i.e. the signal goes RIGHT to LEFT: IN is the input, _IN is the microcontroller – frarugi87 Dec 1 '15 at 15:28
  • @frarugi87 - I copied it straight from a schematic I'm working on(makes sense to me, as I did it ;)), thanks for pointing it out, I will edit it tomorrow when I get a chance. – RSM Dec 1 '15 at 15:39
  • Of course, but it took me a while to understand it ;) anyway thank you for sharing, I'll tkeep it in my mind next time I'll need this kind of converters ;) – frarugi87 Dec 1 '15 at 15:54

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