I've recently purchased an Arduino Pro Mini, 3.3V version. I've planned to use it in a diy remote: I've empty a ps2 remote, just left the buttons, and the board will be inside. The remote will be wireless: I use an xbee, which also fit inside the ps2 controller. To power it, I use a one cell Lipo, which will empower the Arduino and the XBee, here comes my issue: As you've seen, there will be many things an a single ps2 controller, so I try to minimize connections and external components. But, the XBee will take more than the maximum 150mA provided by internal regulator of the Arduino. So, either I use an external regulator, or I directly plug the lipo in the VCC pin if the Arduino. Can the board survive? If the voltage is greater than 3.3V, will it damage the board?

  • also, is that XBEE 3V3 or 5V? You should be ok just connecting the lipo directly to 3.3V+. May 17, 2016 at 22:00
  • I removed the 3v3 regulator on my pro mini by accidentally connecting a lipo directly to the Vcc pin, which roasted the regulator enough to desolder itself! Luckily, no other damage. Oct 20, 2023 at 14:58

1 Answer 1


The only thing about the 3.3V Pro Mini that is actually 3.3V is the 3.3V regulator. The main chip (pretty much the only other component) is good for anything from 1.8V up to 5.5V.

Running direct from a 3.7V LiPo or Li-Ion will be perfectly fine. You might want to disconnect or otherwise disable the regulator though to reduce current consumption - the latest Minis have a solder jumper SJ1 for doing just that, but older versions you may want to actually cut the 3.3V OUT pin of the regulator or de-solder it entirely.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.