The code of ISR executes twice

Question

i am using Arduino Mega.. ANd this is the code:

void bump(void);

void setup() 
{
    pinMode(19,INPUT);
    attachInterrupt(4,bump,HIGH);
    pinMode(13,OUTPUT);
}

void loop() 
{

}

void bump()
{
   for(float i = 0; i < 90000; i++){
   digitalWrite(13,HIGH);
   }
   for(float i = 0; i < 10000; i++){
   digitalWrite(13,LOW);
   }

}  

Although i give +5 V to it once, the LED will blink twice...! What is the solution?

Answer 1

After wondering over it for quite a long time, I finally came to the conclusion, that the interrupt should be made to trigger at RISING edge, if I want it to go into ISR the moment it gets HIGH.

Hence the setup line was change to

attachInterrupt(4,bump,RISING);

And the cod e works well.
I suppose that is because, when it receives a HIGH signal, than the period for which it receives HIGH is a bit long, during which it adds another interrupt into the queue, and so the ISR is executed once again.