3

I have an Arduino Uno R3. I have a paddlewheel waterspeed sensor that I use on an ISR on pin 2. The power supply is approximately 8v stepped down to 4.92v with a circuit yanked from the phone charger. I have also tried this with the arduino 5v.

The pin returns the correct values with digitalRead(), so it's cycling between 1 and 0.

The ISR works fine on pin3. Why does it work on pin 3 and not pin 2 ISR?

void itest() {
    Serial.println( "test" );
}

void setup() {
    attachInterrupt(0, itest, FALLING);
}
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5
  • Have you compared the disassembled code when using each pin?
    – Ignacio Vazquez-Abrams
    Mar 31, 2014 at 1:21
  • Can you show us the code of the ISR and how you registered it?
    – jfpoilpret
    Mar 31, 2014 at 5:19
  • Where do you set pinMode() of pin 2 to INPUT?
    – jfpoilpret
    Mar 31, 2014 at 11:18
  • @jfpoilpret it doesn't need pinMode() and the ISR is hidden by the arduino code in the attachInterrupt
    – Lesto
    Mar 31, 2014 at 19:48
  • I hope you haven't forgotten to change attachInterrupt(0,itest,FALLING); to attachinterrupt(1,itest,FALLING);
    – explorer
    Apr 24, 2015 at 8:48

1 Answer 1

Reset to default
3

never use Serial inside an interrupt handler, increment a (volatile) variable and print it in the loop().

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