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Mar 26, 2023 at 18:14 comment added stevo @jsotola ah ok thanks. I did not really realize this body diode inside the MOSFET. now it makes sense. Do you have any idea, why Arduino uses this type of circuit: Where current can flow to the usb device?
Mar 26, 2023 at 16:18 comment added jsotola @stevo the question about the circuit is not about arduino ... it belongs at electronics.stackexchange.com/questions ... anyway, look closely at the MOSFET symbol ... MOSFETs contain a body diode
Mar 26, 2023 at 16:07 comment added stevo -KIIV A schottky diode sounds actually nice, but there will be a voltage drop (even when its much less than a normal diode). Probably about 0.2-0.3V which result in a power loss of 90mW @300mA current consumption.
Mar 26, 2023 at 15:56 comment added stevo @jsotola Yes, that was exactly my idea. Actually is very simple in my situation: My RPI is connected with a cable soldered to the usb plug of the Arduino (just because of space problems) -> so I just have to disconnect the 5V pin But I'm more interested in an "professional" solution also I'm very curious why the this circuit with the FDN340P is not working as I thought!
Mar 25, 2023 at 19:44 history became hot network question
Mar 25, 2023 at 19:19 comment added jsotola get a short USB type A extender and cut the 5 V wire inside the extender cable
Mar 25, 2023 at 19:11 history edited jsotola CC BY-SA 4.0
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Mar 25, 2023 at 18:19 comment added KIIV In previous work coworkers solved this by adding Schottky diode to the cable usb cable. But it's also possible to change 3V3 reg to 1.8 and connect VIN with 5V (It's turning off the mosfet if VIN is 2 times 3V3)
Mar 25, 2023 at 14:05 answer added st2000 timeline score: 2
S Mar 25, 2023 at 11:43 review First questions
Mar 25, 2023 at 17:12
S Mar 25, 2023 at 11:43 history asked stevo CC BY-SA 4.0