Timeline for What is the ideal way to check if time on ESP8266 via NTP is ready?
Current License: CC BY-SA 4.0
14 events
when toggle format | what | by | license | comment | |
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Apr 4, 2023 at 11:13 | answer | added | shumifan49 | timeline score: -1 | |
Apr 4, 2023 at 10:15 | answer | added | shumifan49 | timeline score: 1 | |
Feb 2, 2023 at 17:06 | vote | accept | Nick Bolton | ||
S Dec 9, 2022 at 16:14 | vote | accept | Nick Bolton | ||
Dec 9, 2022 at 16:14 | |||||
Dec 7, 2022 at 14:00 | answer | added | 6v6gt | timeline score: 3 | |
Dec 6, 2022 at 11:09 | history | edited | Nick Bolton | CC BY-SA 4.0 |
added 170 characters in body
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Dec 6, 2022 at 11:06 | vote | accept | Nick Bolton | ||
S Dec 9, 2022 at 16:14 | |||||
Dec 6, 2022 at 9:48 | history | edited | Nick Bolton | CC BY-SA 4.0 |
edited title
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Dec 5, 2022 at 22:05 | comment | added | DataFiddler | I guess, localtime even starts at 31-Dec-1969 afternoon in a western time zone. Thus comparing the local year with 70 is really a strange approach. Rather test the raw time_t value. | |
Dec 5, 2022 at 21:42 | answer | added | Edgar Bonet | timeline score: 3 | |
Dec 5, 2022 at 21:09 | comment | added | Nick Bolton |
Unfortunately, it doesn't seem to return -1 . When the year is 70 , the result from time is 18 (I guess that's how many seconds the device has been online). When the year is valid, it returns expected epoch, e.g. 1670274493 .
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Dec 5, 2022 at 21:01 | comment | added | Edgar Bonet |
Doesn't time() return −1 if it cannot get the time? At least that is what it is supposed to do.
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Dec 5, 2022 at 20:52 | history | edited | Nick Bolton | CC BY-SA 4.0 |
added 114 characters in body
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Dec 5, 2022 at 20:38 | history | asked | Nick Bolton | CC BY-SA 4.0 |