Timeline for DS3231 RTC module and battery problem
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 29, 2019 at 10:35 | comment | added | Gerben | So the 0.05V is the difference between "no power connected to the Vcc pin" and "5V connected to the Vcc pin"? In that case the 0.05V drop when no power is applied, is most likely due to the battery voltage sagging a bit because a bit power is being drawn from it. I wouldn't worry about that. | |
| Jun 28, 2019 at 17:31 | comment | added | Majenko | That looks like it's in series with the diode to limit the charge current. It has the exact same effect as removing the diode - it breaks the circuit. | |
| Jun 28, 2019 at 16:50 | comment | added | ElectronSurf | i'm using a multimeter to measure the voltage, and i removed THIS resistor. | |
| Jun 28, 2019 at 16:25 | comment | added | Majenko | I don't know what resistor you are on about. If you are going by the voltage that is printed on the battery: that is only a "nominal" value and is less accurate than the 0.05v difference you are measuring anyway. | |
| Jun 28, 2019 at 15:54 | vote | accept | ElectronSurf | ||
| Jun 28, 2019 at 15:53 | comment | added | ElectronSurf | i removed the 200 ohm resistor and kept the diode, the voltage is now dropped to 3.8V which is 0.05V more than battery voltage. is that 0.05V gonna be a problem? | |
| Jun 28, 2019 at 14:58 | history | answered | Majenko | CC BY-SA 4.0 |
