Timeline for Arduino Robot won't move
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Feb 17, 2017 at 13:59 | comment | added | Daniël Verloop | Sean, it seems like I wasn't clear enough myself. I use the Vin port for my battery pack. I use a breadboard to make all the wiring. The breadboard itself is connected to the 5V port on my arduino. | |
| Feb 17, 2017 at 5:00 | comment | added | Sean.D | I do know about amps and voltage. I thought I explained good enough, but looks like I did not. The pin he is using is the 5v, not the Vin pin, the Vin pin takes power into the arduino, the 5v supplies power out to a device connected to the arduino. I was also trying to mention that a double AA battery has 7 Amps, I tested it with my multi meter many times. He has a pack, meaning it is wired in series and not parrel. I am saying his circuit is wrong. & amps is to much for the arduino. A 9v supplies about 2 amps. That is max for arduino, so it will be fine. I am considering volts and amps. | |
| Feb 16, 2017 at 21:22 | comment | added | linhartr22 | Sean, I read it the same way Mark did. I'm not sure if this is a language issue or if you need to study a little more about what current and Amps mean.Circuits will always follow Ohms law. From this you would know that voltage and resistance determine how much current a circuit will draw from it's source. If the source can't deliver that much current you'll get unreliable or no results. If the source can deliver more current it doesn't force more current into the circuit. | |
| Feb 15, 2017 at 19:07 | comment | added | Sean.D | The battery is not drawing, I never said that. The Vin pin is taking in voltage from the battery. Measure the Amps of a 9v and a double AA battery, you will notice a difference. All I am saying is that the 5v outputs power and not input power. Please read what I said again, I think you're misinterpreting what I am saying. | |
| Feb 15, 2017 at 17:58 | comment | added | Mark Smith | Your understanding of the way current is drawn is flawed. A circuit will draw a current - the battery cannot somehow pump a specific current through a circuit. The short-circuit current produced by six AA batteries is not a useful or meaningful here. | |
| Feb 15, 2017 at 17:25 | history | answered | Sean.D | CC BY-SA 3.0 |