Timeline for What is the relationship between the gain on the receiver and the delay time
Current License: CC BY-SA 3.0
9 events
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Oct 12, 2015 at 19:31 | comment | added | Majenko | I said no, it is not nanoseconds, it is loop counts. You could calculate how long it is by counting the instructions in the loop and working out how many clock cycles in total the loop takes, multiplying it by that number. | |
Oct 12, 2015 at 19:16 | comment | added | Jonathan | yes, so that "how long to wait" part is in nanoseconds i presume? | |
Oct 12, 2015 at 19:00 | comment | added | Majenko |
It's not nanoseconds - its loop counts, but that is pretty irrelevant, it's just a period of time. rxcenter starts the reading at the center of a bit - give it time to arrive, but not too long - just the first bit after the leading edge of the start bit. rxintra is how long to wait between each successive bit, and rxstop is how long to wait to sample the stop bit. tx is like rxintra but for transmitting.
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Oct 12, 2015 at 18:52 | comment | added | Jonathan | So does rxcenter wait that many nanoseconds after receiving the startbit, the rxintra waits that many ns between each subsequent payload bit, and the rxstop waiting that long for the stop bit(even though there is no stop bit)? Am I understanding that right? ^^ | |
Oct 12, 2015 at 18:40 | comment | added | Majenko | They are how long to wait before looking at the state of the line for a specific bit (rx...) or how long to wait between sending each bit (tx) | |
Oct 12, 2015 at 18:12 | comment | added | Jonathan | Can you please explain what are the purposes of rxcenter, rxintra, rxstop, and tx? | |
Oct 12, 2015 at 18:10 | comment | added | Jonathan | Thank you so much sir. That was an amazing answer. Thank you so much! | |
Oct 12, 2015 at 18:09 | vote | accept | Jonathan | ||
Oct 7, 2015 at 9:35 | history | answered | Majenko | CC BY-SA 3.0 |